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how much float is available for Activity H if Activity B is delayed by four days and Activity E is delayed by

John works as a project manager of the NHQ Project. He has created the project network diagram
as shown in the figure:

Based on the project network diagram, how much float is available for Activity H if Activity B is
delayed by four days and Activity E is delayed by two days?

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A.
Zero

B.
One

C.
Four

D.
Five

Explanation:
The path of ABEHJ will take 22 days to complete and cannot exceed 28 days or else the project
will be late. If Activity B takes four additional days and Activity E takes two additional days, this
adds (4+2= 6) six days to the path, bringing the path’s duration to exactly (22+6 = 28) days. There
is no available float left for Activity D or H. Float or total float (TF) is the total amount of time that a
schedule activity may be delayed from its early start date without delaying the project finish date,
or violating a schedule constraint. It is calculated by using the critical path method technique and
determining the difference between the early finish dates and late finish dates.
Answer options B, C, and D are incorrect. There is no float available because the path’s duration
has increased to 28 days.


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