A security administrator would like to write an access rule to block the three IP addresses given
below. Which of the following combinations should be used to include all of the given IP
addresses?
192.168.12.255
192.168.12.227
192.168.12.229
A.
192.168.12.0/25
B.
192.168.12.128.28
C.
192.168.12.224/29
D.
192.168.12.225/30
C.
0
0
I suppose that 192.168.12.255 is incorrect. /29 contains 6 hosts. If 255 was replaced with 225, then Answer C would work.
0
0
255 cant be correct, in anycase that would be a broadcast, so it has to be C and assuming its 225
0
0
The correct one is A. /25 would make two subnets. 0-128 and 129-256. 128-2= 126 hosts per subnet or network.
0
0
I don’t think any of the answers are correct.
Blocking the 192.168.12.224/27 subnet is what we want.
0
0