You have been asked to come up with a subnet mask that will allow all three web seivers to be on the same network while proving the maximum number of subnets. Which network address and subnet mask meet this requirement?
A.
192.168.252.8 255.255.255.252
B.
192.168.252.16 255.255.255.252
C.
192.168.252.8 255.255.255.248
D.
192.168.252.0 255.255.255.252
E.
192.168.252.16 255.255.255.240
why?
0
0
i guess 3 ip for servers + broadcast + network = 5 ip addresses that need 3 bits, so subnet mask should be 255.255.255.248.
0
0