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Identify the four valid IPv6 addresses. (Choose four.)

Identify the four valid IPv6 addresses. (Choose four.)

PrepAway - Latest Free Exam Questions & Answers

A.
A

B.
:: 192:168:0:1

C.
2000::

D.
2001:3452:4952:2837::

E.
2002:c0a8:101::42

F.
2003: dead: beef:4dad:23:46:bb: 101

Explanation:
IPv6 addresses are normally written as eight groups of four hexadecimal digits, where each group is separated by a colon (:). For example,
2001:0db8:85a3:0000:0000:8a2e:0370:7334 is a valid IPv6 address. To shorten the writing and presentation of addresses, several simplifications to the notation are permitted. Any leading zeros in a group may be omitted; thus, the given example becomes 2001 :db8:85a3:0:0:8a2e:370:7334 One or any number of consecutive groups of 0 value may be replaced with two colons 2001:db8:85a3::8a2e:370:7334
This substitution with double-colon may be performed only once in an address, because multiple occurrences would lead to ambiguity. For example, the illegal address notation
2001::FFD3::57ab, could represent
2001:0:0:0:0:FFD3:0:57ab
2001:0:0:0:FFD3:0:0:57ab
2001:0:0:FFD3:0:0:0:57ab and
2001:0:FFD3:0:0:0:0:57ab
Using the double-colon reduction the localhost (loopback) address, fully written as 0000:0000:0000:0000:0000:0000:0000:0001, may be reduced to ::1 and the undetermined IPv6 address (zero value), i.e., all bits are zero, is simply::.
For example, the addresses below are all valid and equivalent:
2001:0db8:0000:0000:0000:0000:1428:57ab
2001:0db8:0000:0000:0000::1428:57ab
2001:0db8:0:0:0:0:1428:57ab
2001:0db8:0:0::1428:57ab
2001:0db8::1428:57ab
2001:db8::1428:57ab

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