Refer to the exhibit.

The router address 192.168.1.250 is the default gateway for both the Web Server 2 and Host 1.
What is the correct subnet mask for this network?

A.
255.255.255.250

B.
255.255.255.128

C.
255.255.255.252

D.
255.255.255.0

Explanation:
Based on the information provided in the exhibit, we know that the IP address of the interface Fa0/0 is 192.168.1.250/24, that is to say the subnet mask is 255.255.255.0??
When configuring the correct IP address and not wasting IP address, the network of 192.168.1.0 needs to contain the following three IP addresses of interfaces:
R1 (fa 0/0): 192.168.1.250
Hostl: 192.168.1.106/24 Web seiver 2: 192.168.1.10/24
The correct mask is 255.255.255.0.