Refer to the diagram. All hosts have connectivity with one another. Which statements describe the addressing scheme that is in use in the network? (Choose three.)
A.
The subnet mask in use is 255.255.255.192.
B.
The subnet mask in use is 255.255.255.128.
C.
The IP address 172.16.1.25 can be assigned to hosts in VLAN1
D.
The IP address 172.16.1.205 can be assigned to hosts in VLAN1
E.
The LAN interface of the router is configured with one IP address.
F.
The LAN interface of the router is configured with multiple IP addresses.
VLAN 2 has 114 hosts so we need to leave 7 bits 0 for the host addresses (2^7 – 2 = 126 > 114). Notice that we are working with class B (both Host A and Host B belong to class B) and the default subnet mask of class B is /16 so we need to use 16 – 7 = 9 bits 1 for the sub-network mask, that means the subnet mask should be 255.255.255.128 -> B is correct.
By using above scheme, C is correct because the IP 172.16.1.25 belongs to the sub-network of VLAN 1 (172.16.1.0/25) and can be assigned to hosts in VLAN 1.
For communication between VLAN 1 and VLAN 2, the LAN interface of the router should be divided into multiple sub-interfaces with multiple IP addresses -> F is correct.
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