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Which IPv6 address is valid? adminApril 22, 2014 Which IPv6 address is valid? A.2031:0:130F::9C0:876A:130B B.2001:0DB8:0000:130F:0000:0000:08GC:140B C.2001:0DB8:0:130H::87C:140B D.2031::130F::9C0:876A:130B Show Answer
Sylvain says: August 8, 2012 at 11:37 am Answer A. You can’t use ‘::’ twice. Hence D is incorrect. These values are in hexadecimal format (0 to F). Hence B&C are incorrect. 0 0
Alboma says: August 16, 2012 at 5:27 pm As above post mentions, values are hex from 0 to F. Answer B and C have value G and H, so they’re incorrect. 0 0
Drexx says: July 29, 2013 at 10:51 pm Oh my God. Thanks a lot for your answer! God bless you greatly!!! 0 0
dank says: August 27, 2013 at 1:46 am minor details lol you look fast and you really focus on no double :: and valid beginning 0 0
arooj says: May 2, 2016 at 4:29 pm why 2001:0DB8:0:130H::87C:140B is correct as “::” means 0:0:0:0 so it became 10 pairs of 16bits. RIGHT ??? 0 0
Somebody can explain this question?
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Answer A.
You can’t use ‘::’ twice. Hence D is incorrect.
These values are in hexadecimal format (0 to F). Hence B&C are incorrect.
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can someone explain why B and C are incorrect?
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As above post mentions, values are hex from 0 to F. Answer B and C have value G and H, so they’re incorrect.
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Thanks so much for the answer…
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Oh my God. Thanks a lot for your answer! God bless you greatly!!!
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minor details lol you look fast and you really focus on no double :: and valid beginning
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i make the same mistake
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thanks so much for the explaination – Sylvain and Alboma
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why 2001:0DB8:0:130H::87C:140B is correct as “::” means 0:0:0:0
so it became 10 pairs of 16bits. RIGHT ???
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