Which two subnetworks would be included in the summarized address of 172.31.80.0 /20? (Choose two.)
A.
172.31.17.4 /30
B.
172.31.51.16 /30
C.
172.31.64.0 /18
D.
172.31.80.0 /22
E.
172.31.92.0 /22
F.
172.31.192.0 /18
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How you have calculated the range in subnets
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+ With 172.31.80.0 /20 => use 4 bits for network 172.31.x.x
+ With 4 bits, we can have 16 subnets, they comprise:
172.31.0.0
172.31.16.0
172.31.32.0
172.31.48.0
172.31.64.0
172.31.80.0
……
+ In subnet 172.31.80.0 /20, if we use more 2 bits (172.31.80.0 /22) to divide subnets, we will get more 4 subnetworks, and they include:
172.31.80.0 /22
172.31.84.0 /22
172.31.88.0 /22
172.31.92.0 /22
As the result, the correct answer is D & E.
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