Refer to the output of the corporate router routing table shown in the graphic:
The corporate router receives an IP packet with a source IP address of 192.168.214.20 and a destination address of 192.168.22.3. What will the router do with this packet?
A.
It will encapsulate the packet as Frame Relay and forward it out interface Serial 0/0.117.
B.
It will discard the packet and send an ICMP Destination Unreachable message out interface FastEthernet 0/0.
C.
It will forward the packet out interface Serial 0/1 and send an ICMP Echo Reply message out interface serial 0/0.102.
D.
It will change the IP packet to an ARP frame and forward it out FastEthernet 0/0.
http://www.indiabix.com/networking/ip-routing/discussion-143 — has the graphic
0
0
The output is:
Corp#sh ip route
[output cut]
R 192.168.215.0 [120/2] via 192.168.20.2, 00:00:23, Serial0/0
R 192.168.115.0 [120/1] via 192.168.20.2, 00:00:23, Serial0/0
R 192.168.30.0 [120/1] via 192.168.20.2, 00:00:23, Serial0/0
C 192.168.20.0 is directly connected, Serial0/0
C 192.168.214.0 is directly connected, FastEthernet0/0
(From: http://www.indiabix.com/networking/ip-routing/discussion-143)
Explanation:
Since the routing table shows no route to the 192.168.22.0 network, the router will discard the packet and send an ICMP destination unreachable message out interface FastEthernet 0/0, which is the source LAN where the packet originated from.
0
0
General interview questions at a glance click @ http://skillgun.com
0
0