4 Comments on “which address and mask combination a summary of the routes learned by EIGRP?”

1. mr_tienvu says:

   January 20, 2012 at 8:47 am

   The binary version of 20 is 10100.
   The binary version of 16 is 10000.
   The binary version of 24 is 11000.
   The binary version of 28 is 11100.
   The subnet mask is /28. The mask is 255.255.255.240.

   
   
   
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2. og says:

   October 23, 2012 at 1:48 am

   From the output above, EIGRP learned 4 routes and we need to find out the summary of them: +
   192.168.25.16+ 192.168.25.20+ 192.168.25.24+ 192.168.25.28
   -> The increment should be: 28 – 16 = 12 but 12 is not an exponentiation of 2 so we must choose
   16 (24). Therefore the subnet mask is /28 (=1111 1111.1111 1111.1111 1111.11110000) =
   255.255.255.240
   So the best answer should be 192.168.25.16 255.255.255.240

   
   
   
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3. Green Hosting says:

   August 24, 2013 at 10:14 am

   From the output above, EIGRP learned 4 routes and we need to find out the summary of them:
   + 192.168.25.16
   + 192.168.25.20
   + 192.168.25.24
   + 192.168.25.28

   -> The increment should be: 28 – 16 = 12 but 12 is not an exponentiation of 2 so we must choose 16 (24). Therefore the subnet mask is /28 (=1111 1111.1111 1111.1111 1111.1111 0000) = 255.255.255.240

   So the best answer should be 192.168.25.16 255.255.255.240

   
   
   
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4. networkmanagers says:

   October 31, 2016 at 12:51 am

   Correct answer is

   
   
   
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