If an Ethernet port on a router was assigned an IP address of 172.1.1.1/20, what is the maximum number of hosts allowed on this subnet?
A.
4094
B.
1024
C.
8190
D.
2046
E.
4096
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Please can you explain how you got 4094. Because when i work it out i get
11111111.11111111.00010100.00000000
So host = 2^13 – 2 ?
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Ok ok i got it. Its class B. Sorry my bad.
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Easiest way to work it out: So you have 32 bits and you are masking the first 20 bits for networks leaving 12 bits for hosts address per network. (32-20=12). Total number of valid host is : (2^12=4096)- 2= 4094 (first reserved to represent each the network and last the broadcast address for that network)
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LoL i got this question in my CCNA exam today 😀
And I already knew the answer :DD
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shere your explain if you can?
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In the prefix /20 we have 12 bit 0s so the number of hosts-per-subnet is 212 – 2 = 4094.
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In the prefix /20 we have 12 bit 0s so the number of hosts-per-subnet is 2^12 – 2 = 4094.
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