Your company has a main office and four branch offices. The main office contains a server named Server1 that
runs Windows Server 2012.
The IP configuration of each office is configured as shown in the following table.
You need to add a single static route on Server1 toensure that Server1 can communicate with the hostson all
of the subnets.
Which command should you run?
A.
route.exe add -p 10.10.0.0 mask 255.255.252.0 10.10.0.1
B.
route.exe add -p 172.16.16.0 mask 255.255.252.0 10.10.0.1
C.
route.exe add -p 10.10.0.0 mask 255.255.252.0 172.16.0.0
D.
route.exe add -p 172.16.18.0 mask 255.255.252.0 10.10.0.1
This is to test how you can summarize subnets. There is fast technique to find subnetmask for summarization, you can refere to CCNA book, but for MCSE, I think it will not be complicate. So to solve this type of question, list bits for right most non-zero octet.
16 00010000
17 00010001
18 00010010
19 00010011
So router to summarize the 4 routes to 1 route, router can take all the 4 paths as 000100xx, which means the first 6 bits of the octet should not change, which in turn means, it’s part of subnet mask. So, 252 (128+64+32+16+8+4). So, subnet mask is 255.255.252.0.
Now when you summarize routes, you found subnetmask first, then you just find the first subnet among the summarized route, which is 172.16.16.0.
It seems a bit hard at first, but as you practice, it’s not that hard. And this is very essential when you work. When you get IP addresss from ISP or you have to give them your needed IP pools for NAT, you have to understand this subnetting and summarization.
1
0
16 = 16 + 0
17 = 16 + 1
18 = 16 + 2
19 = 16 + 3
the base is 16 then Network address is : 172.16.16.0
0,1,2,3 can be expressed in 2 last digit of the third Byte in binary witch belong the SubNet , then 2 + 8 = 10 last bit for SubNet
then the network is (32 -10 = 22) /22 or 255.255.252.0
answer is B : route.exe add -p 172.16.16.0 mask 255.255.252.0 10.10.0.1
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B – route.exe add -p 172.16.16.0 mas 255.255.252.0 10.10.0.1
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