An Address Book entry of 104.26.208.0 with a mask of 255.255.255.224 includes which two (2) host addresses?

A.

104.26.208.1

B.

104.26.208.31

C.

104.26.208.224

D.

104.26.208.240

E.

104.208.26.255

Explanation:This question requires a bit ofsubnetting. An excellent resource to learn this is http://www.learntosubnet.com.

Now the part we have to look into is thesubnetmask255.255.255.224. Thesubnetmaskdefines which hosts are in the same subnet or not. In this case we look at 224. First we must convert this decimal number do the binary format. 224 decimalis :11100000 in binary. As you can see the first 3 bits are1’s ,so we have 5 bits left for our hosts. So we can 00000 till 11111 for our hosts. Letsconvert that back to decimal 00000 = 0 and 11111 = 31 in decimal format. In this scenario 104.26.208.1 and 104.26.208.31 would be in the same subnet.

seenagapesays:I have the same idea. AB

0

0