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which action should the technician take to correct Ann’s problem?

Ann, a new user, is unable to communicate on the network from her computer. A technician has
verified that the cables are functioning properly. Based on the information below, which action
should the technician take to correct Ann’s problem?
Computer_A Switch_A
IP: 10.0.0.60 Int VLAN10
SM: 255.255.255.0 IP address 10.0.0.1/28
GW: 10.0.0.1 Speed 100 Duplex Full

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A.
Change the duplex on the switch interface to half

B.
Change the speed on the switch interface to 10Mbps

C.
Change the subnet mask of the computer to 255.255.255.240

D.
Change the IP address of the computer to 10.0.0.12

5 Comments on “which action should the technician take to correct Ann’s problem?

    1. chris says:

      You change the IP address to 12. the maximum subnet would be 16. You would think that you would pick 255.255.255.240. But this is a VLAN. /28 mask bits gives you the range for available ip address are 10.0.0.0-10.0.15. I could be wrong, maybe some expert could jump in. Just giving my 2 cents. hope this helped.




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    2. Aj says:

      Based on the CIDR /28 (255.255.255.240)
      – Gives you 14 available hosts range 1-14
      – Broadcast address 10.0.0.15
      The next subnet is 10.0.0.16 which makes 10.0.0.60 an invalid IP for subnet 10.0.0.0 therefore, changing the mask to 255.255.255.240 will not resolve the user’s connectivity issue.




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  1. chris says:

    You change the IP address to 12. the maximum subnet would be 16. You would think that you would pick 255.255.255.240. But this is a VLAN. /28 mask bits gives you the range for available ip address are 10.0.0.0-10.0.15. I could be wrong, maybe some expert could jump in. Just giving my 2 cents. hope this helped.




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  2. Harry says:

    This question is a joke. It could be that the Interface for VLAN10 (Int VLAN10) has been configured with an IP address of 10.0.0.1/28. Like everyone else said, anyone in VLAN10 would need to be in network 10.0.0.0 with an IP address in the 10.0.0.2 – 10.0.0.14 range. With a current IP address of 10.0.0.60, you are not on the 10.0.0.0 subnet.




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