Refer to the Exhibit.
An administrator is configuring a storage device as shown in the Exhibit.
What is the expected effect on the stated device after running the command?
A.
I/O will rotate on all storage targets regardless of port group state.
B.
I/O will rotate on all storage targets that are Active Optimized state only.
C.
I/O will rotate on all storage targets that are Active Unoptimized state only.
D.
I/O will rotate on all storage targets that are on Available Nodes only.
Explanation:
Explanation/Reference:
http://www.yellow-bricks.com/2011/03/29/alua-and-the-useano-setting/
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This article is most interesting:
https://pubs.vmware.com/vsphere-50/index.jsp?topic=%2Fcom.vmware.vcli.examples.doc_50%2Fcli_advanced_storage.8.2.html
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Switch -useANO
If set to 1, the round robin PSP includes paths in the active, unoptimized state in the round robin set.
If set to 0, the PSP uses active, unoptimized paths only if no active optimized paths are available.
Otherwise, the PSP includes only active optimized paths in the round robin path set.
https://pubs.vmware.com/vsphere-60/topic/com.vmware.vcli.examples.doc/cli_advanced_storage.8.2.html#473243
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B
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- -useANO
-U
If set to 1, the round robin PSP includes paths in the active, unoptimized state in the round robin set. If set to 0, the PSP uses active, unoptimized paths only if no active optimized paths are available. Otherwise, the PSP includes only active optimized paths in the round robin path set.
As per the above option, correct answer is C.
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Answer is B. Second part of the Statement is a double negative. “the PSP uses active, unoptimized paths only if no active optimized paths are available”. This means it will always use optimized paths first, if useano=0.
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No, the answer is B. If, and only if, there were no active optimized paths then useano=0 would result in the use of unoptimized paths. There is no indication in this question stating that there are no optimized paths so it would just be silly to jump to the conclusion that there aren’t any.
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After reading the article and understanding useano=0, I agree, the answer is B.
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yeah, found a few articles on this one. I agree that it will in fact use Active Optimized first…then if none exist, it’ll use Active Unoptimized paths. I guess B is the most correct answer, but the word “only” at the end is wrong. It will in use unoptimized active path if it has to.
https://code.vmware.com/web/dp/doc/preview?id=1499#https%3A%2F%2Fvdc-repo.vmware.com%2Fvmwb-repository%2Fdcr-public%2Fa22374e8-38ce-422f-b262-367d73647919%2F924c9940-05f3-4910-b9fb-7623da51d812%2Fdoc%2Fcli_advanced_storage.8.2.html
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–useANO = “use (A)ctive (N)ot (O)ptimized”
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