DRAG DROP
You plan to deploy a DHCP server that will support four subnets. The subnets will be
configured as shown in the following table.
You need to identify which network ID you should use for each subnet.
What should you identify?
To answer, drag the appropriate network ID to the each subnet in the answer area.

References:
Exam Ref: 70-410: Installing and Configuring Windows Server 2012 R2, Chapter4:
Deploying and configuring core network services, Objective 4.1: Configure IPv4 and IPv6
addressing, p.192, 196
This question is a bit “tricky”, because the nets are all “Class A” networks, but you can do it the same. The trick is to find out how many hosts gives us each /xx
10.10.1.0/26
This network has a “natural mask” of 8.0.0.0
As it has /26, we know that we need 3 bytes filled with ones, and part of the 4th one (2 bits more, 8*3 +2), as in :
11111111.11111111.11111111.11000000
This /26 mask gives us the last part as hosts, so we have 6 zeroes that we can play,
so 2**6 = 64
64 hosts.
We substract two (network and broadcast),gives us 62 hosts.
The nearer one is Subnet1 that needs 50 hosts
/22 gives us 11111111.11111111.11111100.00000000 ,
so we have 8+2 hosts possible
2**10 = 1024
1024-2=1022 possible hosts, so this will be Subnet4
/25=11111111.11111111.11111111.10000000
we have 7 zeroes, so
2**7= 128
128-2= 126 possible hosts:
that will be Subnet2
And the last one is the one is left:Subnet3 = /23
/26 = Subnet1
/22 = Subnet4
/25 = Subnet2
/23 = Subnet3
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Just use the paper they give you and quickly do the maths.
Start with
/24 = 256 (everyone should know this) the create a table by doubling/halving. Remember to subtract two for gateway and broadcast address.
/22 1024
/23 512
/24 256
/25 128
/26 64
/27 32
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Thanks @David, clear and easy to remember.
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While you can and should know how to do the math, the question is easier to answer than that. Just match the subnet masks from largest to smallest with the same largest to smallest order of required hosts.
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Yup
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Jeremy, very good point…
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@jeremy – – do you have other samples based on your technique?
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