You have a server named Server1 that runs Windows Server 2012 R2.
You plan to create a storage pool that will contain a new volume.
You need to create a new 600-GB volume by using thin provisioning. The new volume must
use the parity layout.
What is the minimum number of 256-GB disks required for the storage pool?

A.
2
B.
3
C.
4
D.
5
Explanation:
Based on the RAID calculators, in order to do a parity drive (raid 5) of 600GB will require at
least 4 drives.
References:
http://technet.microsoft.com/en-us/library/hh831391.aspx
http://www.ibeast.com/content/tools/RaidCalc/RaidCalc.asp
http://www.raid-calculator.com/default.aspx
https://www.icc-usa.com/raid-calculator
3×256 GB for volume + 1×256 GB for parity
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I have wrong answer
Storage pool dont use RAID, it has own similat to RAID tehnology
Dave is correct in Thin provision minimal requirement is 3 drives for parity layout.
For fixed volume you need 4 drives
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3 drives is correct – the key in the question is thin provisioning. RAID5 doesn’t come into it
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4 Drives. You need 3 drives to make the capacity greater than 600 GB. Don’t forget You lose one drive for parity in a RAID5. So the answer is 4.
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Yep. You made me see the light. 3 drives are needed for parity, and since it is thin, a 4th is not needed to exceed the size of the drive. However if it was thick provisioned, then you would need a 4th drive.
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Microsoft dont use thick provision therm, it’s from VMWare.
Microsoft use only thin or fixed .
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Parity applies at the Virtual disk level, not at the volume level. I believe this question is purposefully misleading. When you create the virtual disk, you specify the type of disk to create: Simple, Mirror or Parity. Once the virtual disk is created, you create your volume and choose either Thin or Fixed Provisioning. There is no option for a “Parity” volume.
Therefore, regardless of the volume type this will require 4 Disks. Because, even if the disk is Thin Provisioned, it could grow beyond the capacity of a 3 disk parity virtual disk (Total capacity = Disk Capacity * (Number of disks – 1) or 256 * (3-1) = 512 < 600GB).
Here's a great explanation of storage pools: http://blogs.technet.com/b/yungchou/archive/2012/08/31/windows-server-2012-storage-virtualization-explained.aspx
The answer should be C: 4.
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I would go with answer B just because they mention “thin provisioning”. It’s not the same as RAID.
http://www.hardware-revolution.com/microsoft-storage-space-configuration/
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i have added 3 disk on my server..250 GB x 3
Created storaged pool with 3 disk.
and i created new volume on this pool with 3 disk ….set one disk for parity and as this provision…
and in the end specify size….i wrote 2 TB. thats it…
answer is B.
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I second the B – if it says thin provisioned then it doens´t matter how much space you actually got. You only need at least 3 disks in pool to be able to choose Parity. Then you can create volume as big as you please.
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Vietnam Right!
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No mention of raid in the question, so it must be B
BUT – Windows 2012 R2 comes with Parity Spaces , requiring 3 disks minimum,
3 x 256 = 768gb – 600gb = 168GB, is 168GB enough space for the Parity Slabs to be used? Is that why C is the correct answer? check this – http://www.eightforums.com/general-support/16615-confused-storage-spaces-parity-free-space.html
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The question ask us 3 things:
– 600-GB volume by using THIN provisioning
– volume must use the parity layout (VOLUME not storage pool)
– What is the minimum number of 256-GB disks required for the storage pool?
Just for sure, I tried to make a 2 Disk Storage Space. Then, of course, your are not able to create a Virtual Disk with parity. You need minimal of 3 disk in storage space for parity virtual disk.
I think answer is B, 3 disk. You cannot use 600Gb but you can create a 600Gb volume
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KEY WORD ” THIN PROVISIONING” … ANSWER IS 3
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