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Which two actions should you perform?

You administer two servers that run Windows Server 2012 R2. Both servers are part of a Hyper-V cluster. The
servers are configured as shown in the following diagram:

All of the .vhdx files are stored on DISK1.
You observe that the physical input/output (I/O) performance degrades when .vhdx files are accessed.
You need to improve performance.
Which two actions should you perform? Each correct answer presents part of the solution.

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A.
Run the Windows PowerShell command Set-BCCache 10.

B.
On each host server, enable write caching for DISK1.

C.
Run the Windows PowerShell command GetClusterSharedVolumeBlockCacheSizeInMB = 0.

D.
Run the Windows PowerShell command (GetCluster).SharedVolumeBlockCacheSizeInMB = 512.

E.
Run the Windows PowerShell command Get-ClusterSharedVolume “Disk1” | Set- ClusterParameter
CsvEnableBlockCache 1.

F.
On each host server, disable write caching for DISK0.

Explanation:
D: Configuring CSV Cache
Windows Server 2012 R2

4 Comments on “Which two actions should you perform?

  1. Matt says:

    Use Cluster Shared Volumes in a Failover Cluster
    http://technet.microsoft.com/en-us/library/jj612868.aspx#BKMK_cache

    By default in Windows Server 2012, the CSV cache is disabled. In Windows Server 2012 R2, the CSV cache is enabled by default. However, you must still allocate the size of the block cache to reserve.

    To configure the CSV cache
    1. Start Windows PowerShell as an administrator.
    2. To define a cache of 512 MB to be reserved on each node, type the following: (Get-Cluster).BlockCacheSize = 512
    3. Get-ClusterSharedVolume “Cluster Disk 1” | Set-ClusterParameter CsvEnableBlockCache 1




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    1. bkrank says:

      For Windows 2012 (not R2) the answer is correct, D and E. But the question says 2012 R2. If that is the case, then you don’t need to enable the cache, but by default it is 0, so you still need to allocate memory, so it’s just one step, which is:
      (Get-Cluster). BlockCacheSize = 512
      or whatever size you want it to be.

      IOW, 2012 requires two steps and 2012 R2 requires one step, and that commend is different in R2.




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