Your company has a main office and four branch offices. The main office contains a server
named Server1 that runs Windows Server 2012 R2.
The IP configuration of each office is configured as shown in the following table.
You need to add a single static route on Server1 to ensure that Server1 can communicate
with the hosts on all of the subnets.
Which command should you run?
A.
route.exe add -p 10.10.0.0 mask 255.255.252.0 10.10.0.1
B.
route.exe add -p 172.1 6.16.0 mask 255.255.252.0 10.10.0.1
C.
route.exe add -p 10.10.0.0 mask 255.255.252.0 172.16.0.0
D.
route.exe add -p 172.16.18.0 mask 255.255.252.0 10.10.0.1
Explanation:
These parameters will allow communication with all the hosts.
References:
Exam Ref: 70-410: Installing and Configuring Windows Server 2012 R2, Chapter4:
Deploying and configuring core network services, Objective 4.1: Configure IPv4 and IPv6
addressing, p.192, 196
Can someone explain to me why the answer is B
Or should B look like this: route.exe add -p 172.16.0.0 mask 255.255.252.0 10.10.0.1
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0
172.16.16.0 mask 255.255.252.0 mean rang 172.16.16.0-172.16.19.255 so this range included all branched
2
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the answer is c. the server 1 is main office which is 10.10.0.0 network then connecting to the 172.16.0.0 network
0
1
That is wrong as routing on its own subnet is not a issue.
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by supernetting branch 1 to branch 4 self… u get 172.16.15.0 as a single network to communicate with main office… so answer is c
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B is correct
gateway is 10.10.0.1
For example, to add a static route to the 10.0.0.0 network that uses a subnet mask of 255.0.0.0, a gateway of 192.168.0.1, and a cost metric of 2, you type the following at a command prompt:
route add 10.0.0.0 mask 255.0.0.0 192.168.0.1 metric 2
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B is correct. The solution of Jaido enables clients to set up communication with the server.
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C is totally wrong since the route is set up to a network (ending with 0) and not even to a gateway!
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The answer is correct. Please don’t confuse people. There’s a tiny typo and the answer shouldn’t have a “space” between 1 and 6 and should read:
route.exe add -p 172.16.16.0 mask 255.255.252.0 10.10.0.1
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172.16.16.0 /22 = first ip 172.16.16.1, last ip 172.16.19.254 (.255 = broadcast).
So B is correct
You create a persistent route to all those subnets and use 10.10.0.1 as gateway.
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route add -p 172.16.16.0(destination) mask 255.255.252.0 10.10.0.1(gateway)
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stupid question (there’s just 1 gateway at the main office, why add statics on servers let network devices do what they are good at)
Only B makes sense.
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If B is correct (and sets a static route to Branch Office 3), why is D not just as correct (setting a static route to Brach Office 1)?
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I agree. I get that B is the correct answer, but wouldn’t D be correct as well?
Class B networks only looks at the first 2 octet as the network, i.e 172.16.x.x.
This means the 172.16.0.0 network includes both 172.16.16.0 and 172.16.18.0 in it, so either answer should be correct?
If you plug in the numbers in here:
http://www.subnetmask.info/
And then list the networks, you’ll see what I mean.
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default subnetmask of Class B is 255.255.0.0 , however you can use 255.255.255.0
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The correct answer is B.
Just to let you know My friends, usually is a small company a System admin does the network administration. so knowing the networking concepts is a must.
I will explain why the answer is B, using an easiest way by converting to binary, even the answer is so clear just by looking to the proposed options:
I will convert only the third digit
172.16. 0001 0000. 0
172.16. 0001 0001. 0
172.16. 0001 0010. 0
172.16. 0001 0011. 0
as you see the common part of all the subnets is: 172.16. 0001 (22 bits in common)
so to get the network, fill the rest with 0
172.16. 0001 0000. 0 ========> 172.16.16.0 /22
This is a very very basic way, I dont use it because its a class/beginner demonstration.
Hope it helps
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I think the common bit is (20)
8.16.(17,18,19,20)
so the subnet should start from 21
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B is correct.
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Is this really a 70-410 question?
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