Which two statements describe the IP address 10.16.3.65/23? (Choose two.)
A.
The subnet address is 10.16.3.0 255.255.254.0.
B.
The lowest host address in the subnet is 10.16.2.1 255.255.254.0.
C.
The last valid host address in the subnet is 10.16.2.254 255.255.254.0
D.
The broadcast address of the subnet is 10.16.3.255 255.255.254.0.
E.
The network is not subnetted.
Explanation:
The mask 255.255.254.0 (/23) used with a Class A address means that there are 15 subnet bits
and 9 host bits. The block size in the third octet is 2 (256 – 254). So this makes the subnets in 0,
2, 4, 6, etc., all the way to 254. The host 10.16.3.65 is in the 2.0 subnet. The next subnet is 4.0,
so the broadcast address for the 2.0 subnet is 3.255. The valid host addresses are 2.1 through
3.254
B & D
Converting /23 to dotted decimal: 254
The increment for these subnets is 2 (256 – 254)
The first subnet begins at 10.16.0.0
The second subnet ranges from 10.16.2.0 to 10.16.3.255
The first usable host on this subnet is 10.16.2.1 (answer B)
The broadcast address of this subnet is 10.16.3.255 (answer D)
Every other answer is incorrect.
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