An administrator is working with the 192.168.4.0 network, which has been subnetted with a /26
mask. Which two addresses can be assigned to hosts within the same subnet? (Choose two.)
A.
192.168.4.61
B.
192.168.4.63
C.
192.168.4.67
D.
192.168.4.125
E.
192.168.4.128
F.
192.168.4.132
Explanation:
Only the values of host with 67 and 125 fall within the range of /26 CIDR subnet
mask, all others lie beyond it.
192.168.4.0/26
192
11111111=8
168
11111111=8
4
11111111=8
0
11=2
Total 26 bits turned on
Subnet Mask
1st octet 128+64+32+16+8+4+2+1=255
2nd octet 255
3rd octet 255
4th octet 128+64=192
255.255.255.192
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Number of subnets=2 to the power of the number of mask bits which is 2 from the last octet. 2×2=4
Number of hosts=2 to the power of the number of unmask bits which is 6 minus 2. (2x2x2x2x2x2)-2=62 usable hosts.
From there you list out the four subnets and figure which two answers fall with in the same subnet.
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