Which IP addresses are valid for hosts belonging to the 10.1.160.0/20 subnet? (Choose three.)
A.
10.1.168.0
B.
10.1.176.1
C.
10.1.174.255
D.
10.1.160.255
E.
10.1.160.0
F.
10.1.175.255
Explanation:
All IP address in IP ranges between : 10.1.160.1 and 10.1.175.254 are valid as shown below
Address: 10.1.160.0 00001010.00000001.1010 0000.00000000
Netmask:255.255.240.0 = 2011111111.11111111.1111 0000.00000000
Wildcard:0.0.15.25500000000.00000000.0000 1111.11111111
Which implies that
Network: 10.1.160.0/20 00001010.00000001.1010 0000.00000000
HostMin:10.1.160.100001010.00000001.1010 0000.00000001
HostMax:10.1.175.25400001010.00000001.1010 1111.11111110
Broadcast:10.1.175.25500001010.00000001.1010 1111.11111111
Strange explanation for this one. The wild card mask is irrelevant.
Just ensure you work out the subnet mask and how many possible hosts this could have in it.
A /20 network must have the subnet mask 255.255.240.0. If working this out binary, you will discover this leaves 12 0’s for the host portion. (2 ^ 12) – 2 = 4094 available hosts.
You can then work out that this will go from 10.1.160.0 – 10.1.175.254 as you can divide 4094 by 256 to give you 16, which means 160,161,162,163,164,165,166,167,168,169,170,171,172,173,174,175 = 16 lots of addresses, and then ofcourse reserving 160.0 as the network to 175.255 for the address.
Hope that helps explain it a little better.
0
0
That is true Adam!
What i did then is expecting that they is counting each broadcast from each subnet such /24, i know is wrong but i s what i did
0
0