Refer to the exhibit.
Ephone 1 has three active calls. The first two calls were inbound calls, which the user put on hold
to place a third call outbound. What will happen on ephone 1 when a fourth call arrives for
extension 2001?
A.
The fourth call will be delivered to ephone 1 because it only received two inbound calls, one call
less than the busy-trigger-per-button setting.
B.
The fourth call will be delivered to ephone 1 because the huntstop channel setting is not yet
saturated.
C.
The fourth call will be delivered to ephone 1 because it can handle up to five calls on each
button.
D.
The fourth call will be held temporarily by the IOS Software until ephone 1 disconnects one of
the active calls.
E.
The fourth call will not be delivered and the caller will hear a user busy tone.
Explanation:
Because on line maximum 4 calls can be placed when user put the call on hold is
consume a channel and reach the maximum number of calls on line.
the answer is E but I dont know why and how ? is it related to the hunt stop channel which is 4 ? but this is the forth call only means the 5th call need to give busy tone as per my understanding .an anyone explain the answer ?
0
0
the two inbound calls use 2 incoming lines which gets deducted from:
huntstop channel (set to max 4 – incoming calls)
Max calls button (set to 5 – incoming and outgoing calls)
Busy trigger per button (set to 3 Incoming calls)
As there is only one button the and no shared line shown the huntstop channel is greater than busy trigger so not used.
The two inbound calls are placed on hold – this is done by sending an invite to CM – using outbound channel – deducting 2 from the max calls per button leaving only 1 channel which is used for the 3rd outgoing call.
when the 3rd call comes in there are no channels left.
0
0