You have a server named Server1 that runs Windows Server 2012 R2.
You plan to create a storage pool that will contain a new volume.
You need to create a new 600-GB volume by using thin provisioning. The new volume must use the
parity layout.
What is the minimum number of 256-GB disks required for the storage pool?
A.
2
B.
3
C.
4
D.
5
Explanation:
It takes 3 discs (minimum) in order to create a storage pool array with parity. If this array were using
fixed provisioning, this would not be enough given the 256MB capacity (since only 2/3rds of 256 X 3 –
less than 600 – could be used as actual data with the rest being parity bits), but since this array uses
thin provisioning, a 600GB volume could technically be set up on a 20GB disc and it would still show
as 600GB. (So, essentially, the question really becomes how many drives it takes in a storage pool to
create a parity array.)
References:
http://technet.microsoft.com/en-us/library/hh831391.aspx
http://www.ibeast.com/content/tools/RaidCalc/RaidCalc.asp
http://www.raid-calculator.com/default.aspx
https://www.icc-usa.com/raid-calculator
Answer is B – 3 Disks to create a parity layout
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Answer is C!
When using Parity Layout u lose the storage of 1 disk. so when we need 600 GB and only would have 3 Disks with 256 GB Storage, we would have effective only 512GB. So the answer is C, that we have enough storage.
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Bart says:
April 9, 2015 at 1:19 pm
Agree:
Parity – This is a striped set with distributed parity by striping data and parity information across multiple disks, similar to RAID 5. It increases reliability with reduced capacity. This configuration requires at least three disks to protect data from a single disk failure, and cannot be used in a failover cluster.
http://blogs.technet.com/b/yungchou/archive/2012/08/31/windows-server-2012-storage-virtualization-explained.aspx
The answer is B. (!)Thin(!) provisioned means ONLY virtual limits (MAX 64 TB within 2012 R2)
(!)Thick(!) provisioned the answer would be C.
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Agreed. Even the explanation below the answer describes a situation where B is still the answer because of the way ‘thin’ provisioning works.
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