What two address and subnet combinations are properly matched? (Choose two.)
A. 10.230.33.15/28
B. 10.32.11.67/27
C. 172.16.255.255/14
D. 172.25.44.96/26
E. 192.168.73.223/29
20 Comments on “What two address and subnet combinations are properly matched?”
Tsusays:
B and D
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Tsusays:
B C D
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joshsays:
anyone know the real answer to this?
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Ranger99says:
B and C
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Ranger99says:
Actually, Tsu was right and BCD are correct (just checked this), so you can consider this question fake.
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jamiesays:
A and E are bradcast addresses. BDC are correct.
You just need to change the addresses to binary and check it yourselfs.
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Adamsays:
Um, isn’t C also a broadcast address (since last octet is 255)?
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Willyxsays:
172.16.255.255/14
assuming that we can use a /14 subnet in a B class (we shouldn’t):
/14=255.252.0.0 , the magic number is 4. We have
172.0.0.0 as first subnet ID
172.4.0.0 as first subnet ID
172.8.0.0 as first subnet ID
then we have a range of 172.4.0.1 to 172.7.255.254 and 172.7.255.255 is the broadcast address.
No, 172.16.255.255/14 isn’t a broadcast address, just the mask is wrong in a B class 🙂
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Willyxsays:
Sorry: then we have a range of 172.16.0.1 to 172.19.255.254 and 172.19.255.255 is the broadcast address.
:p
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Willyxsays:
Sorry folks,
B/D are right.
C is wrong cause a class B should not have a subnet <16 bit.
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JMSsays:
B/D are right.
C is wrong cause a class B should not have a subnet <16 bit.
I agree with you Willyx.
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cantmisssays:
So why not A and E? Both of those are broadcast addresses, while B and D are Hosts.
But WHY is B/D correct? That has NOT been explained. As I mentioned, A/E match in the context that they are both broadcasts as well.
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Galantesays:
B/D are correct, they are both valid IP address within their subnet
A: 10.230.33.15/28 is the broadcast address for the network with subnet mask 255.255.255.240
D: 172.25.44.96/26 is the Network ID based on the subnet mask 255.255.255.192
E: 192.168.73.223/29 is the broadcast address for the network with subnet mask 255.255.255.248
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Galantesays:
Let me expand on my last comment ..
B/D are correct, they are both are valid HOST IP addresses within their subnet, whereas A,D & E are either the subnet IP or broadcast IP addresses.
Hope they helps?
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cantmisssays:
The question doesnt ask what is valid, it just ask what matches.
B and D
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B C D
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anyone know the real answer to this?
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B and C
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Actually, Tsu was right and BCD are correct (just checked this), so you can consider this question fake.
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A and E are bradcast addresses. BDC are correct.
You just need to change the addresses to binary and check it yourselfs.
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Um, isn’t C also a broadcast address (since last octet is 255)?
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172.16.255.255/14
assuming that we can use a /14 subnet in a B class (we shouldn’t):
/14=255.252.0.0 , the magic number is 4. We have
172.0.0.0 as first subnet ID
172.4.0.0 as first subnet ID
172.8.0.0 as first subnet ID
then we have a range of 172.4.0.1 to 172.7.255.254 and 172.7.255.255 is the broadcast address.
No, 172.16.255.255/14 isn’t a broadcast address, just the mask is wrong in a B class 🙂
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Sorry: then we have a range of 172.16.0.1 to 172.19.255.254 and 172.19.255.255 is the broadcast address.
:p
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Sorry folks,
B/D are right.
C is wrong cause a class B should not have a subnet <16 bit.
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B/D are right.
C is wrong cause a class B should not have a subnet <16 bit.
I agree with you Willyx.
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So why not A and E? Both of those are broadcast addresses, while B and D are Hosts.
Hosts match a type,
Broadcasts match a type
Which is the correct match?
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B/D are right
there are change in dumb
here 12 new questions update 11/4/2016
https://www.dropbox.com/s/t3cst7guoqebjwh/640—911.rar?dl=0
please if any one slutions and sure the questions share with us
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http://certcollection.org/forum/topic/285413-ccna-data-center-640-911-exam/
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But WHY is B/D correct? That has NOT been explained. As I mentioned, A/E match in the context that they are both broadcasts as well.
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B/D are correct, they are both valid IP address within their subnet
A: 10.230.33.15/28 is the broadcast address for the network with subnet mask 255.255.255.240
D: 172.25.44.96/26 is the Network ID based on the subnet mask 255.255.255.192
E: 192.168.73.223/29 is the broadcast address for the network with subnet mask 255.255.255.248
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Let me expand on my last comment ..
B/D are correct, they are both are valid HOST IP addresses within their subnet, whereas A,D & E are either the subnet IP or broadcast IP addresses.
Hope they helps?
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The question doesnt ask what is valid, it just ask what matches.
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BD are valid address. just try use it on your pc
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C is also valid
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