Refer to the exhibit.
The five routers shown in the exhibit are successfully implementing OSPF on the interface shown
in the exhibit. The exhibit also shows settings for OSPF areas and interface costs.
A network administrator enters these commands on Router 4 and Router 5:
How can the administrator ensures that Router 2 learns the route to 172.16.0.0/16 with next hop
10.0.0.6?
A.
On Router 2, enables OSPF ECMP globally
B.
On Router 4 and 5, change the metric type for redistributed static routes to type 1
C.
On Router 4, change the cost for redistributed static routes to 2
D.
On Router 2, 3, 4 and 5, change the bandwidth reference value to 100
Explanation:
there are new questions please update dumps
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When redistributing outer network with OSPF, you can use two metric types (1, 2).
Default using type is 2, just apply its interface’s cost.
In this case, R5’s interface would be selected because it costs lower than R4.
But if you choose type 1, it aggregates the whole interfaces’ costs through the outer network.
In this case, R2 – R4 – 172.16.0.0/16 cost would be 10 + 5 = 15
R2 – R3 – R5 – 172.16.0.0/16 cost would be 5 + 10 + 1 = 16
R4’s interface would be selected because it costs lower than going to R5.
So B is correct answer.
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But do someone know about inputted command to R5
“ip route-static 172.16.0.0 16 type 2 172.16.0.5”
what does it exactly mean?
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