You want the default permissions for your files to be -rw-r—– .
HOW must you set umask?
A.
037
B.
640
C.
038
D.
027
Explanation/Reference:
A) removes the directory permission g-x making the g+r permission pointless
B) would result in –x-wxrwx, which is not what we want
C) is not a octal number used for umask
Correct Answer: D
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the comment box is not for the answers
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-rw-r—– should be 137
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For directories, the base permissions are (rwxrwxrwx) 0777 and for files they are 0666 (rw-rw-rw).
Therefore umask 027 is correct.
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027 is correct. However the explanation seems slightly out of context as the question does not refer to symbolic mode action.
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Answer should be 026
Default filepermission: 666 – 640 = 026
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The default for a new directory is 777(rwxrwxrwx). 777-750 = 027
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It must be 027 because you want to set the default permissions for (all) your files. So you need to edit the umask for your directory.
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I have been saying the same thing
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but 026 is not listed as an answer, you should pick 027 which also give the correct permission
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