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If a disk drive’s rotational speed is 10000 revolutions per minute, what is its average rotational laten seenagapeAugust 23, 2012 If a disk drive’s rotational speed is 10000 revolutions per minute, what is its average rotational latency? A.0.003 milliseconds B.0.05 milliseconds C.3 milliseconds D.5 milliseconds Show Answer
SP says: March 8, 2013 at 5:31 pm (1 / (RPM / 60)) * 0.5 * 1000 Or, in other words: 30000 / RPM Result in ms. So 30000 / 10000 = 3 miliseconds 0 0
SP says: March 8, 2013 at 5:36 pm Forgot to explain: The average rotational latency for a disk is half the amount of time it takes for the disk to make one revolution so (1 / (RPM / 60)) * 0.5 * 1000 0.5 is for the half RPM/60 to get it in seconds and * 1000 to covert to miliseconds 0 0
Must says: May 10, 2013 at 6:45 am rpm = rotational per minute (½)/ (X/60)= “60/2X” X is 10000 > 10k = 60/(2×10) = 3 ms 0 0
L. Freitas says: November 9, 2015 at 5:31 pm RPM = 10000 Average Seek Time is equal a half of a turn, Rotacional per second (rps) = Rotational per minute/60. A half a turn is (1/2 or 0,5)/(rps). R = (0,5)/(RPM/60) R = (0,5)/(10000/60) R = 0,5 / 166.6 <- rps R = 0,003 seconds or 3 milliseconds. :) \O/ \O/ \O/ 0 0
whats the formulae for the latency??
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anybody knows how to calculate ?
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(1 / (RPM / 60)) * 0.5 * 1000
Or, in other words:
30000 / RPM
Result in ms.
So 30000 / 10000 = 3 miliseconds
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Forgot to explain:
The average rotational latency for a disk is half the amount of time it takes for the disk to make one revolution
so (1 / (RPM / 60)) * 0.5 * 1000
0.5 is for the half
RPM/60 to get it in seconds and * 1000 to covert to miliseconds
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rpm = rotational per minute
(½)/ (X/60)= “60/2X”
X is 10000 > 10k = 60/(2×10) = 3 ms
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RPM = 10000
Average Seek Time is equal a half of a turn,
Rotacional per second (rps) = Rotational per minute/60.
A half a turn is (1/2 or 0,5)/(rps).
R = (0,5)/(RPM/60)
R = (0,5)/(10000/60)
R = 0,5 / 166.6 <- rps
R = 0,003 seconds or 3 milliseconds. :)
\O/ \O/ \O/
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