A customer has a 300 GB primary MirrorView/S image. The image workload is 5,000 IOPs of
random 16 KB I/Os with a read/write ratio of 4:1. The secondary image is fractured for 20 seconds
as the result of a connectivity failure.
How much data will be copied to the secondary as part of the resynchronization process?
A.
1,250 MB
B.
2,500 MB
C.
2,930 MB
D.
5,860 MB
5000 IOPs , 4:1 > 1000 Writes
Extent size 128KB
128KB x 1000 writes x 20sec= 2560000 or 2500MB.
Answer is B.
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Ice_Man, correct answer is C.
Extent size is 150 kb which is calculated as 1KiB per 2 Gib of source lun. 300/2=150
150kib*1000writes*20sex= 3000000 kib /1024 = 2929.6 mb, which is close to 2930 mb
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Pavel,
Exact, the right answer is C
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