A 512 GB LUN has three clones. While Clone 1 is fractured, and Clones 2 and 3 are in the nonfractured state, a secondary host performs 200 random writes of 4 kB to Clone 1. Clone 1 is then
used in a Protected Restore operation.
How much data is written to the Source LUN by the restore process?
A.
800 kB
B.
12,800 kB
C.
25,600 kB
D.
51,200 kB
Snpaview clones Bloc size is LUN Size in GB.
So in kB : LUNSize(GB)/2, with a minimum of 128kB.
Here, with a 512 GB LUN, extent size will be 256kB.
200 random write x 256kB = 51,200kB
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thanks for explanation
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