You have a Hyper-V host named Served That runs Windows Server 2016. Server1 has a virtual
machine named VM1, VM1 is configured to run the Docker daemon. On VM1 you have a container
network that uses transparent mode. You need to ensure that containers that run on VM1 can
obtain IP addresses from DHCP. What should you do?
A.
On VM1, run docker network connect.
B.
On Server1runGet-VMNetworkAdapter-VMName VM1| Set-VMNetworkAdapter-MacAddressSpoofing On.
C.
On Server1, run docker network connect.
D.
On VM1, run Get-VMNetworkAdapter-VMName VM1| Set-VMNetworkAdapter-MacAddressSpoofing On.
It is D
http://blogs.msmvps.com/russel/tag/mac-address-spoofing/
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It is B. If you try and run just “Get-VMNetworkAdapter-VMName VM1” from within a VM, it won’t work. It has no idea what VM1 is, even if it is VM1. VM1 is a name identified by the Hyper-V host which is why running that command on the host will give a result. Plus, when you think about it, no MAC spoofing is even occurring as far as VM1 is aware. It has a Container that is sending out a MAC address and that is to be expected since all machines send out MAC addresses. What is weird is on the host side because it is seeing VM1 sending out a MAC address that doesn’t belong to it (the containers MAC address). The host has no idea that VM1 has a container on it and will consider it a spoofed MAC address. Therefore, it is the host (Server1 in this case) that you need to run this command on.
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It is B
Explanation can be found here: http://www.aidanfinn.com/?p=18934
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It’s B. UYou must run this cmdlets form server1
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Correct B:
Configure media access control (MAC) address spoofing
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If your container host is virtualized, you must enable MAC address
spoofing. For example, you can type the following Windows PowerShell
command, and then press Enter:
Get-VMNetworkAdapter -VMName Container Host VM | Set-VMNetworkAdapter -MacAddressSpoofing On
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correct answer is B
even if we thought that VM1 has windows 2016 and even thought if we supposed it know GET-VMnetwork without setting mac spoofing from host it will not work
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