Based on the network provided in the exhibit, how to route the traffic arriving at PG-R1 for 10.1.3.1?

A.
through PG-R3, since the path through PG-R3 is through the backbone

B.
through PG-R2, because that is the only path available; no neighbor adjacency will be built between PG-R1 and PG-R2

C.
through PG-R1, since the path through PG-R1 has the lowest hop count

D.
through PG-R1, since the path through PG-R1 has the lowest total metric (10+10=20, versus 10+10+10=30 through PG-R3)