A new department’s local area network has to be connected to the existing LAN using a router. This new department’s LAN uses IP addresses from 192.168.112.64/26 and the first free IP address there was reserved for the router.
How many IP addresses were left for other hosts to be connected?
A.
63
B.
24
C.
61
D.
42
Explanation:
Subnetmask /26 defines 6 Bits for the Subnetaddresses. 6 Bit = 64 Addresses (2^6 = 64). Subtract 2 for Broadcast- and Net-Addresses and 1 for the router, leaves 61 addresses for hosts.
actually there is no correct ansver. C does not substract 3 reserved routers adresses
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WTF?
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Sorry. late nite post. It is correct.
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