After reviewing the design for their new VNX, your customer has requested further explanation of the hot spare algorithm used by the array. You propose the following scenario:
RAID group 200 consists of five 600 GB 10K SAS drives in a RAID 5 configuration. Within this RAID group there are three 25 GiB LUNs. One of the five drives has just failed.
In your scenario, which hot spare drive would the array first select to replace the failed drive?
A.
SAS: 300 GB
B.
SAS: 600 GB
C.
NL-SAS: 2 TB
D.
EFD.100 GB
Answer must be 600GB SAS
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Sahil I think you are incorrect, it’s because the same drive type will still be available in the “hot spare” algorithm it can apply the same drive type as it can adhere to the consumed space.
In this question the consumed space 75GiB therefore a 300GiB drive is sufficient
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Nope, the question is right:
1. Failing drive in-use capacity – The smallest capacity hot spare drive that can accommodate the in-use capacity of the failing drive’s LUNs will be used.
2.Hot spare location – Hot spares on the same back-end port as the failing drive are preferred over other like-size hot spares.
3.Same Drive type – Hot spare must be of the same drive type.
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