Click on the calculator icon in the upper left-hand corner. Your customer wants to use a VNX system at an unmanned DR site. The system will be used exclusively as a secondary MirrorView/A system, and it is capable of performing 60,000 LUN IOPs in this role. The primary system is also a VNX.
If the total primary image workload consists of 1 KiB random I/Os with a R/W ratio of 3:1, what is the maximum bandwidth required for the link between the VNX systems?
A.
240 Mb/s
B.
120 Mb/s
C.
360 Mb/s
D.
600 Mb/s
How do you calculate this?
Since target can handle 60,000 IOPS, all of those IOPS could be write IOPS. To get to the 240 Mb/s every of those IOPS would have to be 4Kb of size. But on the source IOs are 1KiB. So how does this fit together?
I don’t get it.
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Did you get the answer? Trying to figure it out myself
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I think you are dividing by the transfer rate for MirrorView/A is 2KiB.
60,000 IOPS /3 = 20,000 Write IOPS x 1KiB = 20,000 KiB/s = 200,000 KB/s = 200MB/s
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3:1 RW 60000 IOPS => 15000 Write IOPS
15000 IOPS x 1 KiB = 15000 KiB
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3:1 RW 60000 IOPS => 15000 Write IOPS
15000 IOPS x 1 KiB = 15000 KiB
=> 15360000 Bytes
=> 122880000 bits
~> 120 Mb/s (Megabits per second)
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