HTTP protocol specifies that arbitrary binary characters can be passed within the URL by
using %xx notation, where ‘xx’ is the
A.
ASCII value of the character
B.
Binary value of the character
C.
Decimal value of the character
D.
Hex value of the character
D
C
I amend my answer to “D”. So correct answer is D.
You can see from this link: https://books.google.com.tr/books?id=0RfANAwOUdIC&pg=PA720&lpg=PA720&dq=%22xx+notation%22+binary&source=bl&ots=pGMr1qn3tj&sig=xA7eDhA2TtfryHrTYIFu1SR3sBo&hl=tr&sa=X&ei=WlIeVe_2F8K0aamqgrAJ&ved=0CEYQ6AEwBg#v=onepage&q=%22xx%20notation%22%20binary&f=false
i think the answer is D
D https://books.google.nl/books?id=0RfANAwOUdIC&pg=PA720&lpg=PA720&dq=%22xx+notation%22+binary&source=bl&ots=pGMqass7ti&sig=rnIg1xZ78ScUvuIlTmDY3r7REuc&hl=nl&sa=X&ei=8C4dVYe1NorgasrzgoAL&ved=0CEQQ6AEwBQ#v=onepage&q=%22xx%20notation%22%20binary&f=false
This is definitely D! The answer indicated to be correct (C) is NOT done by %xx, but rather &#[y][y]y;
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The answer is undoubtedly “D”! (Not the provided wrong answer C!)
http://www.w3schools.com/tags/ref_urlencode.asp
URL encoding replaces unsafe ASCII characters with a “%” followed by two hexadecimal digits.
For example, %3ctest%3e equals to .
Something in the above comment is escaped by aiotesking web application:
equals to…. ＜test＞
alert “hacked”