Which of the following IP addresses would be hosts on the same subnet given the subnet mask
255.255.255.224? (Select TWO).

A.
10.4.4.125
B.
10.4.4.158
C.
10.4.4.165
D.
10.4.4.189
E.
10.4.4.199
Explanation:
With the given subnet mask, a maximum number of 30 hosts between IP addresses 10.4.4.161 and
10.4.4.190 are allowed. Therefore, option C and D would be hosts on the same subnet, and the other
options would not.http://www.subnetonline.com/pages/subnet-calculators/ip-subnet-calculator.php
Mask = 255.255.255.224
N = Farthest left subnet number which is not 255
Network increment = 256 – N (224) = 32
Net ID 1 = 10.4.4.0 (no IPs in this subnet)
Net ID 2 = 10.4.4.32 (no IPs in this subnet)
Net ID 3 = 10.4.4.64 (no IPs in this subnet)
Net ID 4 = 10.4.4.96 (only 10.4.4.125 is in this subnet)
Net ID 5 = 10.4.4.128 (only 10.4.4.158 is in this subnet)
Net ID 6 = 10.4.4.160 (10.4.4.165 and 10.4.4.189 are in this subnet)
Net ID 7 = 10.4.4.192 (10.4.4.199 is in this subnet)
Therefore correct IPs are C and D.
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