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How much traffic is being passed through the public IP address based on the output displayed above?

An administrator is reviewing the following output:

VIP(141.128.58.149:80:UP:WEIGHTEDRR): Hits(38200495, 18/sec) Mbps(1.02) Pers(OFF)
Err(0) Pkt(186/sec, 610 bytes) actSvc(4) DefPol(NONE) override(0) Conn: Clt(253, 1/sec,
OE[252\]) Svr(3) S(141.128.49.40:80:UP) Hits(9443063, 4/sec, P[2602342, 0/sec\]) ATr(5)
Mbps(0.23)BWlmt(100 kbits) RspTime(112.58 ms) Other: Pkt(36/sec, 712 bytes) Wt(10000)
RHits(31555) Conn: CSvr(42, 0/sec) MCSvr(20) OE(16) RP(11) SQ(0) How much traffic is
being passed through the public IP address based on the output displayed above?

PrepAway - Latest Free Exam Questions & Answers

A.
100 kbits

B.
1.02 Mbps

C.
0.23 Mbps

D.
112.58 ms


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