Refer to the exhibit.
The access list has been configured on the Gi0/0/0/0 interface in the inbound direction. Which four
packets that are sourced from 10.1.1.1 TCP port 1060, if they are routed to the Gi0/0/0/0 interface,
will be permitted? (Choose four)
A.
destination IP address: 192.168.15.37, destination TCP port: 8080
B.
destination IP address: 192.168.15.41, destination TCP port: 8080
C.
destination IP address: 192.168.15.49, destination TCP port: 8080
D.
destination IP address: 192.168.15.36, destination TCP port: 80
E.
destination IP address: 192.168.15.46, destination TCP port: 80
F.
destination IP address: 192.168.15.49, destination TCP port: 80
C.
destination IP address: 192.168.15.49, destination TCP port: 8080
D.
destination IP address: 192.168.15.36, destination TCP port: 80
E.
destination IP address: 192.168.15.46, destination TCP port: 80
F.
destination IP address: 192.168.15.49, destination TCP port: 80
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Hi
How is this possible?
192.168.15.32 with wildcard mask of 0.0.0.15 equates to a Subnet of 192.168.15.32 – 192.168.15.47 so not getting how the ACL is allowing: –
destination IP address: 192.168.15.49, destination TCP port: 80
destination IP address: 192.168.15.49, destination TCP port: 8080
I would of said: –
A.
destination IP address: 192.168.15.37, destination TCP port: 8080
B.
destination IP address: 192.168.15.41, destination TCP port: 8080
D.
destination IP address: 192.168.15.36, destination TCP port: 80
E.
destination IP address: 192.168.15.46, destination TCP port: 80
making these ip’s within the range from the ACL – Can anyone elaborate on why this isn’t the outcome?
Thanks 🙂
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C and E are allowed because of the final “permit ipv4 any any”
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C and F are allowed because of the final “permit ipv4 any any”
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