A customer has a 512 GiB primary MirrorView/S image. The image workload is 1,000 IOPs of random 4 KiB IOs, with a R/W ratio of 3:1. The secondary image is fractured for 30 seconds as the result of a connectivity failure. How much data will be copied to the secondary as part of the resynchronization process?
A.
1.8 GiB
B.
3.0 GiB
C.
5.1 GiB
D.
10.0 GiB
How do you calculate this?
1.8 GiB per 30s means 62914,56 KiB/s. This would equal an IO size of about 252 KiB or 15728,64 4 KiB IOPS.
I don’t get it.
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You have to check extent size, which is 512k for a 512GB LUN (512 x 512 bytes) – these are marked dirty per write. As we have 250 writes per second and a duration of 30 seconds we got 250 x 256k x 30s = 1920000k = 1.8G.
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