When using an N+2:1 protection policy on a 7-node Isilon cluster, how much capacity will be used
to store a 510 KiB file?
A.
638 KiB
B.
640 KiB
C.
766 KiB
D.
768 KiB
Explanation:
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Correct Answer: 768 KiB
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Please give me logic how did u calculated………
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510k fits 4 data stripe units of 128k. Add 2 protection stripe units and you get 768k.
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has anyone got the isilon student guide for me? the provided scribd link in another answer doesn’t work anymore. I need it desperately! thanks anyone!?
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