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An application requires 3.5 TB of capacity. The application generates 2300 IOPS to disks during
peak workloads. The vendor indicates that a 146 GB, 15K rpm drive is capable of performing a
maximum of 150 IOPS.
How many disks are required to meet both capacity and performance requirements?

A.
15
B. 22

C.
24

D.
60

Explanation:
Storage Design based on Application Requirements and Disk Drive Performance

Calculation
Dc = 3.5TB / 146GB
= 3500 / 146
= 23.97
= 24 Drives
Dp = 2300 iops / 150 iops
= 15.33
= 15 Drives
Disk required = max(Dc,Dp)
= max(24,15)
= 24
EMC E10-001 Student Resource Guide. Module 2: Data Center Environment