Refer to the exhibit.
A network administrator is adding two new hosts to Switch
A.
Which three values could be used for the configuration of these hosts? (Choose three.)
host A IP address: 192.168.1.79
A.
Which three values could be used for the configuration of these hosts? (Choose three.)
host A IP address: 192.168.1.79
B.
host A IP address: 192.168.1.64
C.
host A default gateway: 192.168.1.78
D.
host B IP address: 192.168.1.128
E.
host B default gateway: 192.168.1.129
F.
host B IP address: 192.168.1.190
Explanation:
something wrong in this question
where is answer number 3?
and why “A” is 2 times? like it’s part of the question
0
0
Apart from the typo (a wrong copy-paste I suppose), the question and selected answers seem correct to me. This question should be:
A network administrator is adding two new hosts to Switch. Which three values could be used for the configuration of these hosts? (Choose three.)
A.
host A IP address: 192.168.1.79
B.
host A IP address: 192.168.1.64
C.
host A default gateway: 192.168.1.78
D.
host B IP address: 192.168.1.128
E.
host B default gateway: 192.168.1.129
F.
host B IP address: 192.168.1.190
0
0
thanks Typos
0
0
why answer E is wrong ?
the subnet for Vlan 20 is from 192.168.1.129 to 192.168.1.190 …
0
0
In the exhibit above the default gateway has already been given an ip address of 192.168.1.130 so there’s no need for another gateway address
0
0
sorry … the adress should be the one configured in the f0/0.2 in the router … so E is wrong
0
0
First understand what a Point-to-Point link is (just google and c images for a better understanding)
In a Single Point-to-Point link there’re 2 Points (as the name implies), one point each sides
And those Points can be considered as Hosts.
So in a Single Point-to-Point link there are 2 Hosts.
So for a single point-to-point link we must assign 2 valid IPs from a same subnet.
So to have 2 valid IPs the chosen subnet should have at least 4 IPs (2+2=4) (Remember we have to reserve 1 IP for the network ID and 1 IP for Broadcast ID)
I think up to this u have understood what I’m telling
So to have 1 Point-to-Point link we should have
1 Subnet and
4 IPs
So to have 113 Point-to-Point links we should have (at least)
1 x 113 = 113 Subnets
4 x 113 = 452 IPs (Hosts, u may call in subletting world)
So to have 452 IPs we should use a subnet of /27
Because /23 has 9 host bits so it can offer 512 (2^9) IPs and 510 (512-2) valid IPs we can have our required 452 IPs wasting a minimum of IPs
P.S.
/24 subnet can only have 254 ((2^8)-2) valid IPs so not sufficient for our requirement of 452 IPs
and anything less than /23 like /22 /21 /20 /18 can be used for accommodate 452 IPs but we would have to waste more IPs
__
Regards,
Dilshan
0
0