A company has a forest with 4 sites. Subnets are as follows:
MainOffice 172.16.1.0 Subnet: 255.255.255.0 Gateway 172.16.1.254
Site1 192.168.12.0 Subnet: 255.255.255.0
Site 2 192.168.13.0 Subnet: 255.255.255.0
Site 3 192.168.14.0 Subnet: 255.255.255.0
Site 4 192.168.15.0 Subnet: 255.255.255.0
You add a new server to the MainOffice and it needs to be able to communicate to all sites.
Which route command would you run?
A.
route add -p 192.168.8.0 netmask 255.255.252.0 172.16.1.254
B.
route add -p 192.168.0.0 netmask 255.255.248.0 172.16.1.254
C.
route add -p 192.168.12.0 netmask 255.255.252.0 172.16.1.254
D.
route add -p 192.168.12.0 netmask 255.255.240.0 172.16.1.254
Dup of 562
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To do the route summarization you can transform the octet that changes in common for each IP range to bits.
So the 12 until 15 you have:
00001100
00001101
00001110
00001111
Observe that from left to right the numbers repeat until here “000011” so the route that summaries them must count the first 16 bits plus these 6 = 22 bits /22 mask which in decimal is 252.
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