You have a server named Server1 that runs Windows Server 2016. Server1 has the following routing table.
What will occur when Server1 attempts to connect to a host that has an IP address of 172.20.10.50?
A.
Server1 will attempt to connect directly to 172.20.10.50.
B.
Server1 will route the connection to 10.10.0.2.
C.
Server1 will silently drop the connection attempt.
D.
Server1 will route the connection to 192.168.2.1.
Explanation:
http://www.techrepublic.com/article/understanding-routing-tables/
A. Server1 will attempt to connect directly to 172.20.10.50.
On route print there is 172.16.0.0/12 subnet on-link.
HostMin: 172.16.0.1
HostMax: 172.31.255.254
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PETER ARE YOU sure ? have you passed the exam if so please email me mqbankai@gmail.com
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Peter gave the correct answer, sam. 🙂
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First of all you get an IP address (172.20.10.50 ) and you have to know where is this IP located in which range .
1- In the table you’ve got 172.16.0.0 with subnet mask 255.240.0.0 that means that the Cidr is /12 !
Explain why /12 255.240.0.0 equals in BIN 11111111. 11110000. 00000000. 00000000 .
2- you have to increment your ip from the second octet
1 1 1 *1 0 0 0 0
128 64 32 *16 8 4 2 1
You can see that you will increment with 16: that means the beginning is:
172 *0 0 0
172 *16 0 0
172 *32 0 0
172 *48 0 0
172 *64 0 0
and what is the end of the subnets?
172 15 255 255
172 31 255 255
172 47 255 255
172 63 255 255
172 79 255 255
And the host that you want to use are in between. ( 172.16.0.1 – 172.31.255.254)
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