You have a server named Server1 that runs Windows Server 2012 R2.
You plan to create a storage pool that will contain a new volume.
You need to create a new 600-GB volume by using thin provisioning. The new volume must use the
parity layout.
What is the minimum number of 256-GB disks required for the storage pool?
A.
2
B.
3
C.
4
D.
5
Explanation:
It takes 3 discs (minimum) in order to create a storage pool array with parity. If this array were using
fixed provisioning, this would not be enough given the 256MB capacity (since only 2/3rds of 256 X 3 –
less than 600 – could be used as actual data with the rest being parity bits), but since this array uses
thin provisioning, a 600GB volume could technically be set up on a 20GB disc and it would still show
as 600GB. (So, essentially, the question really becomes how many drives it takes in a storage pool to
create a parity array.)
References:
http://technet.microsoft.com/en-us/library/hh831391.aspx
http://www.ibeast.com/content/tools/RaidCalc/RaidCalc.asp
http://www.raid-calculator.com/default.aspx
https://www.icc-usa.com/raid-calculator
Answer should be B. 3
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Agreed. Thin-provisioned so you don’t need the full 600GB available immediately, just three disks for parity.
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agreed. short and nice explanation!
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+1. This is verified from other versions of the same question as well.
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ok but the main question here is… what would microsoft consider correct ? B or C? hahahahaha . thanks guys
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most of these questions have answers like these. wrong answer selected and correct explanation @ the bottom.
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The answer is C. You need 3 disk to get (or be over) 600GB and one more in order to store parity. When you use parity disk you “waste” one disk. If you only pick 3 disks you will get 512 GB (+ parity). IMHO.
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agree with sako Paco
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For parity is necessary one more disk, however in this case, before parity, it says thin provisioning, in thin provisioning it is not necessary all space available, then you dont need one more disk.
The correct answer is B.
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