Refer to the exhibit. The network setup is running the RIP routing protocol. Which two events will
occur following link failure between R2 and R3? (Choose two.)
A.
R2 will advertise network 192.168.2.0/27 with a hop count of 16 to R1.
B.
R2 will not send any advertisements and will remove route 192.168.2.0/27 from its routing
table.
C.
R1 will reply to R2 with the advertisement for network 192.168.2.0/27 with a hop count of 16.
D.
After communication fails and after the hold-down timer expires, R1 will remove the
192.168.2.0/27 route from its routing table.
E.
R3 will not accept any further updates from R2, due to the split-horizon loop prevention
mechanism.
Answer should be A and D.
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R2 poisons the route with the infinite metric and sends it to all interfaces (including to R1).
Then R1 does a poison-reverse which ignores split horizon rules and sends the route back to the originating router. This helps ensure all routers on the segment knows about the change..
If R1 does not receive the poisoned route from R2, it will time out as explained in D.
TL;DR the answer A and C is correct
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Besides, a lot of the new 489Q CCNP 300-101 dumps are available here:
https://drive.google.com/open?id=0B-ob6L_QjGLpZEE0S2YxR3ZMUWs
Best Regards!
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