6 Comments on “What is the output of the following code: echo "1" + 2 * "0x02";”

1. SM Farhad Hossain says:

   May 1, 2016 at 8:06 am

   Answer: is { A. 1 }

   Description : first 2 * “0x02” // “0x02” is string because of double quotation

   2 * “0x02” = 0
   1+0 = 1

   
   
   
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   1. Mia says:

      August 29, 2017 at 4:12 am

      Could you please explain why 2 * “0x02” would return 0?
      Since “0x02” should be equal to the decimal value 2, this would run as 2 * 2 = 4.

      
      
      
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2. ruslanbes says:

   May 1, 2016 at 8:58 pm

   @SM Farhad Hossain
   “0x02” is typecasted to hexadigit number. The given answer is correct

   
   
   
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3. SM Farhad Hossain says:

   May 2, 2016 at 8:27 am

   before PHP 7 this will output 5
   all php 7 will output 1

   
   
   
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   1. Mia says:

      August 29, 2017 at 4:06 am

      Can you explain why this would occur according to you?
      Because when I tested this with PHP 7.0.0 (DEV), it did echo out 5.

      
      
      
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4. mr_tienvu says:

   August 16, 2016 at 8:53 am

   C

   
   
   
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