What is the output of the following command sequence? Exhibit:
A.
a b c
B.
abc
C.
anbncn
D.
token token token
E.
“a ” “b ” “c “
Get 50% Discount on All Your Purchases
at PrepAway.com - Latest Exam Questions
This is ONE TIME OFFER
50%
The correct answer is B.
1
0
I think it is A – note the space before the second “
0
1
The answer is B. Token removes the white spaces so a b c would become abc.
0
0
https://www.ibm.com/support/knowledgecenter/SSPT3X_4.2.0/com.ibm.swg.im.infosphere.biginsights.commsql.doc/doc/r0000719.html
Can somebody explain if you think the answer is wrong??
0
0
I just ran the command –
1. For the above question
for token in a b c;do
echo -n “$token “;
done
Ans – a b c
2. A similar question
for token in a b c;do
echo -n ${token};
done
Ans – abc
To prevent confusion I have posted both variations. Note that when token is in quotes with space, the space between characters is maintained as is. Else all white spaces are removed.
0
0